Solution Manual Heat And Mass Transfer Cengel 5th Edition Chapter 3 |best| -

$\dot{Q}=\frac{423-293}{\frac{1}{2\pi \times 0.1 \times 5}ln(\frac{0.06}{0.04})}=19.1W$

The convective heat transfer coefficient for a cylinder can be obtained from: $\dot{Q}=\frac{423-293}{\frac{1}{2\pi \times 0

(b) Convection:

Alternatively, the rate of heat transfer from the wire can also be calculated by: $\dot{Q}=\frac{423-293}{\frac{1}{2\pi \times 0

$r_{o}=0.04m$